Home
Class 12
PHYSICS
Assertion:- The trajectory of projectile...

Assertion`:-` The trajectory of projectile in `XY` plane is quadratic in `x` and linear in `y` if x is independent of `X-`coordinate.
Reason `:-` `y-`coordinate of trajetory is independent of `x-`coordinate.

A

If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion.

B

If both Assertion & Reason are True but Reason is not a correct explanation of the Assertiion.

C

If Assertion is True but the Reason is False.

D

If both Assertion & Reason are False

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze both the assertion and the reason provided in the question. ### Step-by-Step Solution: 1. **Understanding the Assertion**: The assertion states that the trajectory of a projectile in the XY plane is quadratic in x and linear in y if x is independent of the x-coordinate. - The trajectory of a projectile is generally described by the equations: \[ x = u_x t \] \[ y = u_y t - \frac{1}{2} g t^2 \] where \( u_x \) and \( u_y \) are the horizontal and vertical components of the initial velocity, and \( g \) is the acceleration due to gravity. 2. **Finding the Relationship**: - From the equation for \( x \), we can express time \( t \) as: \[ t = \frac{x}{u_x} \] - Substituting this expression for \( t \) into the equation for \( y \): \[ y = u_y \left(\frac{x}{u_x}\right) - \frac{1}{2} g \left(\frac{x}{u_x}\right)^2 \] - Simplifying this gives: \[ y = \frac{u_y}{u_x} x - \frac{g}{2 u_x^2} x^2 \] - This shows that \( y \) is a quadratic function of \( x \) (since it includes an \( x^2 \) term) and thus confirms that the trajectory is quadratic in \( x \). 3. **Understanding the Reason**: - The reason states that the y-coordinate of the trajectory is independent of the x-coordinate. - However, from our earlier derivation, we see that \( y \) is actually dependent on \( x \) because \( y \) is expressed as a function of \( x \). 4. **Conclusion**: - The assertion is true because the trajectory is indeed quadratic in \( x \). - The reason is false because the y-coordinate is dependent on the x-coordinate. ### Final Answer: - **Assertion**: True - **Reason**: False - Therefore, the correct option is that the assertion is true and the reason is false.

To solve the problem, we need to analyze both the assertion and the reason provided in the question. ### Step-by-Step Solution: 1. **Understanding the Assertion**: The assertion states that the trajectory of a projectile in the XY plane is quadratic in x and linear in y if x is independent of the x-coordinate. - The trajectory of a projectile is generally described by the equations: ...
Promotional Banner

Topper's Solved these Questions

Similar Questions

Explore conceptually related problems

The trajectory of a projectile in a vertical plane is y=sqrt(3)x-2x^(2) . [g=10 m//s^(2)] Time of flight of the projectile is :-

Assertion:- Formation of a law of physics in terms of vectors is independent of the choice of coordinate axes. Reason:- Vector notation often a language in which statement have a physcal constant without ever introducing a coordinate system.

Reduce the equations of the following planes in intercept form and find its intercepts on the coordinate axes: 2x-y+z=5

In the xy-plane above, what is the value of the x-coordinates of Point A minus the y-coordinates of Point B?

The equation (x - 7)^(2) + (y - 8)^(2) = 10 is that of a circle that lies in the standard (x,y) coordinate plane. One endpoint of a diameter of the circle has y-coordinate 11. What is the y-coordinate of the other endpoint of that diameter?

Reduce the equation of the plane 2x+3y-z=6 to intercept form and find its intercepts on the coordinate axes.

See Fig. 3.11 and complete the following statements:(i) The abscissa and the ordinate of the point B are _and _ Hence, the coordinates of B are (__,__).(ii) The x–coordinate and the y–coordinate of the point M are _ and _ respectively. Hence, the coordinates of M are (__,__).(iii) The x–coordinate and the y–coordinate of the point L are _ and _ respectively. Hence, the coordinates of L are (__,__).(iv) The .r–coordinate and the y–coordinate of the point S are _ and _ respectively. Hence, the coordinates of S are (__,__).

The line with the equation 4/5x+1/3y =1 is graphed in the xy‑plane. What is the x-coordinate of the x‑intercept of the line?

A point is on the x–axis. What are its y–coordinate and z–coordinates?

One of the following is an equation of the linear relation shown in the standard (x, y) coordinate plane below. Which equation is it?