In a second ODI match between England and India Bhuwnesh kumar bowled his medium fast bowling. He starts his run up from the distance of `50m` from the stumps (bowling end) and at the time of bowling a ball,his speed is `36(km)//(hr)` and the speed of ball is `144(km)//(hr)`.
If his mass is `70 kg` and mass of the ball is `(1)/(4)kg` and the heat produce in his body is one tenth of the total work done by him, then
Select the incorrect statement `:`

Options

A. Work done by the friction on him is negative
B. Work done by the ball on him is negative
C. Work done by ground on him is zero
D. Work done by the man on the ball is positive.

Explanation

To solve the problem, we need to analyze the situation step by step, focusing on the work done by Bhuvnesh Kumar while bowling and the kinetic energy involved.

### Step 1: Convert Speeds from km/hr to m/s
First, we need to convert the speeds from kilometers per hour (km/hr) to meters per second (m/s).

- Speed of Bhuvnesh Kumar (V1):
\[ V1 = 36 \, \text{km/hr} = \frac{36 \times 1000}{3600} = 10 \, \text{m/s} \]

- Speed of the ball (V2):
\[ V2 = 144 \, \text{km/hr} = \frac{144 \times 1000}{3600} = 40 \, \text{m/s} \]

### Step 2: Calculate the Initial and Final Kinetic Energy of the Ball
Next, we calculate the initial and final kinetic energy of the ball.

- Initial kinetic energy of the ball (KE_initial):
\[ KE_{\text{initial}} = 0 \, \text{(since the ball is at rest)} \]

- Final kinetic energy of the ball (KE_final):
\[ KE_{\text{final}} = \frac{1}{2} m v^2 = \frac{1}{2} \left(\frac{1}{4}\right) (40)^2 = \frac{1}{2} \times \frac{1}{4} \times 1600 = 200 \, \text{J} \]

### Step 3: Calculate the Work Done by Bhuvnesh Kumar on the Ball
The work done by Bhuvnesh Kumar on the ball is equal to the change in kinetic energy of the ball.

- Work done (W):
\[ W = KE_{\text{final}} - KE_{\text{initial}} = 200 - 0 = 200 \, \text{J} \]

### Step 4: Calculate the Heat Produced
According to the problem, the heat produced in his body is one-tenth of the total work done by him.

- Heat produced (Q):
\[ Q = \frac{1}{10} W = \frac{1}{10} \times 200 = 20 \, \text{J} \]

### Step 5: Analyze the Work Done by the Ground and Friction
- The work done by the ground on Bhuvnesh Kumar is zero because the displacement is perpendicular to the normal force exerted by the ground.

- The work done by the friction force on him is negative, but since he is not sliding, the effective displacement due to friction is zero.

### Step 6: Conclusion
Based on the above calculations and reasoning, we can conclude that:

- The work done by Bhuvnesh Kumar on the ball is positive.
- The work done by the ground on him is zero.
- The work done by the ball on him is negative.

The incorrect statement in the problem is regarding the work done by the friction force, which is stated to be negative. The correct interpretation is that the work done by the friction force is zero.