A constant force produces maximum velocity V on the block connected to the spring of force constant K as shown in the figure. When the force constant of spring becomes 4K, the maximum velocity of the block is

Options

A. `(V)/(4)`
B. `2V`
C. `(V)/(2)`
D. `V`

Answer

C

Explanation

At maximum, velocity, `F_(n et)=0rArrF=kx`
By work energy theorem, `W=DeltaKE`
`F_(x)-(1)/(2)Kx^(2)=(1)/(2)mV^(2)-0`
`rArr(F^(2))/(2K)=(1)/(2)mV^(2)rArrVprop(1)/(sqrtK)`