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Velocity of a stone projected, 2 seconds...

Velocity of a stone projected, 2 seconds before it reaches the maximum height, makes angle `53^(@)` with the horizontal then the velocity at highest point will be

A

`20 m//s`

B

`15 m//s`

C

`25 m//s`

D

`80//3 m//s`

Text Solution

Verified by Experts

The correct Answer is:
B
Two second before maximum height `v_(x)=gx`

`tan53=(20)/(V_(x)),v_(x)=15m//s` at maximum height
`v=v_(x)=15m//s`
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