If momentum (P), area (A) and time (T) are taken to be the fundamental quantities then the dimensional formula for energy is:

Options

A. `(P^(1)A^(-1)T^(1))`
B. `(P^(2)A^(1)T^(1))`
C. `(P^(1)A^(-1//2)T^(1))`
D. `(P^(1)A^(1//2)T^(-2))`

Answer

D

Explanation

[Power]=[(work)/(time)]`=`[(forcexxlength)/(time)]
`=[(momentumxxsqrtarea)/(time)^(2)]=[P^(1)A^(1//2)T^(-2)]`