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If vectors vec(A)=(hat(i)+2hat(j)+3hat(k...

If vectors `vec(A)=(hat(i)+2hat(j)+3hat(k))m` and `vec(B)=(hat(i)-hat(j)-hat(k))m` represent two sides of a triangle, then the third side can have length equal to `:`

A

`3m`

B

`4m`

C

`6m`

D

Can not be determined

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The correct Answer is:
To find the length of the third side of the triangle formed by the vectors \(\vec{A}\) and \(\vec{B}\), we can follow these steps: ### Step 1: Write down the vectors Given: \[ \vec{A} = \hat{i} + 2\hat{j} + 3\hat{k} \quad \text{(in meters)} \] \[ \vec{B} = \hat{i} - \hat{j} - \hat{k} \quad \text{(in meters)} \] ### Step 2: Find the resultant vector (third side) The third side of the triangle can be found by adding the two vectors: \[ \vec{C} = \vec{A} + \vec{B} \] Calculating the components: \[ \vec{C} = (\hat{i} + 2\hat{j} + 3\hat{k}) + (\hat{i} - \hat{j} - \hat{k}) \] Combine the like terms: \[ \vec{C} = (1 + 1)\hat{i} + (2 - 1)\hat{j} + (3 - 1)\hat{k} \] \[ \vec{C} = 2\hat{i} + 1\hat{j} + 2\hat{k} \] ### Step 3: Calculate the magnitude of the resultant vector The magnitude of vector \(\vec{C}\) is given by: \[ |\vec{C}| = \sqrt{(2)^2 + (1)^2 + (2)^2} \] Calculating each term: \[ |\vec{C}| = \sqrt{4 + 1 + 4} = \sqrt{9} \] Thus, \[ |\vec{C}| = 3 \text{ meters} \] ### Conclusion The length of the third side of the triangle is: \[ \boxed{3 \text{ meters}} \] ---

To find the length of the third side of the triangle formed by the vectors \(\vec{A}\) and \(\vec{B}\), we can follow these steps: ### Step 1: Write down the vectors Given: \[ \vec{A} = \hat{i} + 2\hat{j} + 3\hat{k} \quad \text{(in meters)} \] \[ ...
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