From a circular disc of radius `R`, a triangular portion is cut (sec figure). The distance of the centre of mass of the remainder from the centre of the disc is `-`

Options

A. `(4R)/(3(pi-2))`
B. `(2R)/(3(pi-2))`
C. `(5R)/(7(pi-2))`
D. `(R)/(3(pi-1))`

Answer

D

Explanation

Ans.(4)
Lot mass per area be `sigma`

`Y_(cm)=(M_(1)(0)-M_(2)((R)/(3)))/(M_(1)-M_(2))=(-R)/(3(pi-1)`