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Consider the following changes: M(s) ...

Consider the following changes:
` M(s) to M(g) " " ...(1)`
`Mg(s) to M^(2+) (g) + 2e^(-) " " ....(2)`
`M(g) to M^(+)(g) + e^(-) " " ....(3)`
`M^(+)(g) to M^(2+) (g) + e^(-) " " ...(4)`
`M(g) to M^(2+) (g) + 2e^(-) " " ....(5)`
The second ionization energy of M could be calculated from the energy values associated with:

A

`a+c+d`

B

`b-a+c`

C

`a+e`

D

`e-c`

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Verified by Experts

The correct Answer is:
D

`N//A`
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