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Which of the following order is not corr...

Which of the following order is not correct?

A

`C_(2)gtCN^(ө)gtO_(2)^(ө)` (`% pi` bond character)

B

`C_(2)^(-2)=N_(2)=NO^(oplus)` (`%sigma` bond character)

C

`O_(2)gtN_(2)^(+)gtC_(2)` (Paramagnetic nature)

D

`C_(2)gtO_(2)gtN_(2)` (`%` of `ABMO` `e^(ө)s`)

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the given orders is not correct, we need to analyze the molecular orbital configurations and properties of the species mentioned. Let's break down the steps involved in solving this problem. ### Step 1: Identify the Molecular Orbital Configurations 1. **C2**: - Total electrons = 12 - Configuration: σ1s² σ1s*² σ2s² σ2s*² π2p² π2p² - Pi electrons = 4, Sigma electrons = 8 2. **CN⁻**: - Total electrons = 14 - Configuration: σ1s² σ1s*² σ2s² σ2s*² π2p² π2p² σ2p¹ - Pi electrons = 4, Sigma electrons = 10 3. **O2⁻**: - Total electrons = 17 - Configuration: σ1s² σ1s*² σ2s² σ2s*² π2p² π2p² π2p*¹ - Pi electrons = 4, Sigma electrons = 10 ### Step 2: Calculate the Percentage of Pi Bond Character - For **C2**: - Percentage of pi bond character = (Number of pi electrons / Total electrons) × 100 = (4/12) × 100 = 33.33% - For **CN⁻**: - Percentage of pi bond character = (4/14) × 100 = 28.57% - For **O2⁻**: - Percentage of pi bond character = (4/17) × 100 = 23.53% ### Step 3: Analyze the Sigma Bond Character - For **C2**: - Sigma electrons = 8 - Percentage of sigma bond character = (8/12) × 100 = 66.67% - For **CN⁻**: - Sigma electrons = 10 - Percentage of sigma bond character = (10/14) × 100 = 71.43% - For **O2⁻**: - Sigma electrons = 10 - Percentage of sigma bond character = (10/17) × 100 = 58.82% ### Step 4: Determine Paramagnetic Nature - **C2**: All electrons are paired → Diamagnetic - **CN⁻**: 1 unpaired electron → Paramagnetic - **O2⁻**: 2 unpaired electrons → Paramagnetic ### Step 5: Calculate Percentage of Anti-bonding Molecular Orbital Electrons - For **C2**: - Anti-bonding electrons = 2 - Percentage = (2/12) × 100 = 16.67% - For **O2**: - Anti-bonding electrons = 2 - Percentage = (2/16) × 100 = 12.5% - For **N2**: - Anti-bonding electrons = 2 - Percentage = (2/14) × 100 = 14.29% ### Step 6: Compare and Identify Incorrect Order After calculating the percentages and properties, we can compare the results to identify which order is incorrect. The final order based on the properties analyzed should be: 1. Percentage of Pi bond character: C2 > CN⁻ > O2⁻ 2. Percentage of Sigma bond character: CN⁻ > C2 > O2⁻ 3. Paramagnetic nature: O2⁻ > CN⁻ > C2 4. Percentage of Anti-bonding electrons: C2 > N2 > O2 ### Conclusion The order that is not correct based on the calculations and comparisons is option D. Thus, the answer to the question is: **Final Answer: Option D is not correct.** ---

To determine which of the given orders is not correct, we need to analyze the molecular orbital configurations and properties of the species mentioned. Let's break down the steps involved in solving this problem. ### Step 1: Identify the Molecular Orbital Configurations 1. **C2**: - Total electrons = 12 - Configuration: σ1s² σ1s*² σ2s² σ2s*² π2p² π2p² - Pi electrons = 4, Sigma electrons = 8 ...
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