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Resonance Hybrid of carbonate ion is :...

Resonance Hybrid of carbonate ion is `:`

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To find the resonance hybrid of the carbonate ion (CO₃²⁻), we will follow these steps: ### Step 1: Determine the Lewis Structure of the Carbonate Ion 1. **Count the total number of valence electrons**: - Carbon (C) has 4 valence electrons. - Each Oxygen (O) has 6 valence electrons, and there are three Oxygens. - The ion has a -2 charge, which means we add 2 more electrons. - Total = 4 + (3 × 6) + 2 = 26 valence electrons. 2. **Draw the basic structure**: - Place the carbon atom in the center and connect it to the three oxygen atoms. ### Step 2: Distribute Electrons 1. **Form bonds**: - Connect the carbon atom to each oxygen atom with single bonds initially. - This uses 6 electrons (3 bonds). 2. **Distribute remaining electrons**: - After forming the bonds, we have 20 electrons left (26 - 6 = 20). - Distribute these electrons to satisfy the octet rule for the oxygen atoms. Each oxygen needs 8 electrons. 3. **Complete the octets**: - Place 6 electrons (3 pairs) around each of the two outer oxygen atoms, making them negatively charged (O⁻). - The central carbon will have only 6 electrons around it at this point. ### Step 3: Create Double Bonds 1. **Form double bonds**: - To satisfy the octet rule for carbon, we can convert one of the single bonds to a double bond. - This can be done with any of the three oxygen atoms, leading to three possible resonance structures. ### Step 4: Draw Resonance Structures 1. **Draw the three resonance structures**: - Structure 1: C=O (double bond) and two O⁻ (single bonds). - Structure 2: C=O (double bond with a different O) and two O⁻ (single bonds). - Structure 3: C=O (double bond with the third O) and two O⁻ (single bonds). ### Step 5: Represent the Resonance Hybrid 1. **Indicate resonance**: - The resonance hybrid is represented by drawing the structures with dashed lines to indicate that the actual structure is a blend of all three. ### Final Representation The resonance hybrid of the carbonate ion can be represented as: - One carbon atom double bonded to one oxygen atom and single bonded to the other two oxygen atoms, which carry a negative charge.

To find the resonance hybrid of the carbonate ion (CO₃²⁻), we will follow these steps: ### Step 1: Determine the Lewis Structure of the Carbonate Ion 1. **Count the total number of valence electrons**: - Carbon (C) has 4 valence electrons. - Each Oxygen (O) has 6 valence electrons, and there are three Oxygens. - The ion has a -2 charge, which means we add 2 more electrons. - Total = 4 + (3 × 6) + 2 = 26 valence electrons. ...
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