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Three particles A, B and C of equal mass...

Three particles` A, B` and `C` of equal mass move with equal speed `V = 5 ms^(-1)` along the medians of an equilateral triangle as shown in the figure. They collide at the centroid `G` of the triangle. After the collision, `A` comes to rest, `B` retraces its path with the speed `V = 5 ms^(-1)`. What is the speed of `C`?

A

`v`

B

`v//2`

C

`2v`

D

information ijnsufficient

Text Solution

Verified by Experts

The correct Answer is:
A
`P_(i)=0`
`P_(i)=0`, So speed of C id equla to that of B and moving in opposite direction.
So Ans. Is v.
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