Total planes containing maximum atoms in `IF_(7)` will be `:-`

Options

A. 1
B. 2
C. 3
D. 4

Answer

To solve the question regarding the total planes containing the maximum atoms in IF7, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding the Structure of IF7**:
- IF7 (iodine heptafluoride) has one iodine atom and seven fluorine atoms. The iodine atom is the central atom surrounded by the fluorine atoms.

2. **Visualizing the Arrangement**:
- The arrangement of the seven fluorine atoms around the iodine atom can be visualized as a pentagonal bipyramidal geometry. This means that there are two distinct planes in the structure.

3. **Identifying the Planes**:
- In the pentagonal bipyramidal structure, one plane consists of five fluorine atoms forming a pentagon, and the iodine atom is at the center.
- The second plane contains the two axial fluorine atoms above and below the pentagonal plane.

4. **Counting Atoms in the Maximum Plane**:
- The plane that contains the maximum number of atoms is the pentagonal plane, which includes five fluorine atoms plus the central iodine atom. Thus, this plane contains a total of 6 atoms (5 F + 1 I).

5. **Determining the Number of Such Planes**:
- Since there is only one unique pentagonal plane in the IF7 structure that contains the maximum number of atoms (6 atoms), we conclude that there is only one plane with the maximum number of atoms.

6. **Final Answer**:
- Therefore, the total number of planes containing the maximum atoms in IF7 is 1.