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Which of the following order of Bond str...

Which of the following order of Bond strength is`/`are correct `:-`
`(a)` `C-CgtS-SgtP-PgtO-O`
`(b)` `H-HgtN=NgtO=OgtF-F`
`(c)` `Cl-ClgtBr-BrgtF-FgtI-I`
`(d)` `2ppi-2ppigt2ppi-3ppigt2ppi-3ppigt3ppi-3ppi`
Option `:-`

A

a, b, c

B

a, c, d

C

c, d

D

Only a

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The correct Answer is:
To solve the question regarding the order of bond strength, we will analyze each option step by step based on the principles of bond strength in chemistry. ### Step-by-Step Solution: 1. **Understanding Bond Strength**: - Bond strength is influenced by the size of the atoms involved. Smaller atoms tend to form stronger bonds due to the shorter distance between their nuclei, which leads to stronger attractive forces. 2. **Analyzing Option (a)**: `C-C > S-S > P-P > O-O` - **C-C bond**: Carbon has a strong bond due to its small size. - **S-S bond**: Sulfur is larger than carbon, leading to a weaker bond than C-C. - **P-P bond**: Phosphorus is larger than sulfur, so its bond is weaker than S-S. - **O-O bond**: Oxygen has a small size but has electron repulsion due to lone pairs, making the O-O bond weaker than the others. - **Conclusion for (a)**: This order is correct. 3. **Analyzing Option (b)**: `H-H > N≡N > O=O > F-F` - **H-H bond**: Hydrogen has a very strong bond due to its small size. - **N≡N bond**: The triple bond between nitrogen is strong, but not as strong as H-H. - **O=O bond**: Oxygen has repulsion between lone pairs, making this bond weaker than N≡N. - **F-F bond**: Fluorine has significant electron-electron repulsion, making this bond the weakest. - **Conclusion for (b)**: This order is incorrect due to the placement of O=O and F-F. 4. **Analyzing Option (c)**: `Cl-Cl > Br-Br > F-F > I-I` - **Cl-Cl bond**: Chlorine has a strong bond due to its size. - **Br-Br bond**: Bromine is larger than chlorine, leading to a weaker bond. - **F-F bond**: Fluorine has significant repulsion due to its small size and high electron density, making it weaker than Br-Br. - **I-I bond**: Iodine is the largest, leading to the weakest bond. - **Conclusion for (c)**: This order is correct. 5. **Analyzing Option (d)**: `2π > 2p > 2π > 3p > 2π > 3p > 3π > 3p` - This option seems to have some errors in notation and repetition. It is unclear and does not provide a valid comparison. - **Conclusion for (d)**: This order is incorrect due to ambiguity. ### Final Conclusion: - The correct orders of bond strength are found in options (a) and (c). Therefore, the correct answer is: - **Correct Options**: (a) and (c)
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