Two cars a and B starts motion with a velocity of `10 m//s` and `20 m//s` respectively. Car a moves with a constant acceleration of `2.5 m//s^(2)` and car B have constant acceleration of `0.5 m//s^(2)` as shown in figure. Find when car A will over take car B. Dimension of car is negligible as compare to distance. Find the time after which car A over takes car B.

Explanation

To solve the problem of when car A overtakes car B, we can use the equations of motion. Let's break down the solution step by step.

### Step 1: Define the Variables
- Let the initial velocity of car A, \( u_A = 10 \, \text{m/s} \)
- Let the initial velocity of car B, \( u_B = 20 \, \text{m/s} \)
- Let the acceleration of car A, \( a_A = 2.5 \, \text{m/s}^2 \)
- Let the acceleration of car B, \( a_B = 0.5 \, \text{m/s}^2 \)

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