a particle moves on a circular path of radius 8 m. distance traveled by the particle in time t is given by the equation `s=2/3 t^(3)`. Find its speed when tangential and normal accelerations have equal magnitude.

Explanation

To solve the problem step by step, we will follow these steps:

### Step 1: Understand the given equation for distance
The distance traveled by the particle is given by the equation:
\[ s = \frac{2}{3} t^3 \]

### Step 2: Find the expression for velocity
Velocity \( v \) is the rate of change of distance with respect to time. We can find it by differentiating the distance equation with respect to time \( t \):
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