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Initially car A is 10.5m ahead of car B ...

Initially car `A` is `10.5m` ahead of car `B` . Both start moving at time `t=0` in the same direction along a straight line. The velocity time graph of two cars is shown in figure. The time when the car `B` will catch the car `A`, will be

A

`t-21` sec

B

`t=2sqrt(5)` sec

C

`20` sec

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A
`S_(B)=S_(A)+10.5`
`t^(2)/2=10t+10.5`
`t^(2)=20t+21`
`t^(2)-20t-21=0`
`t=21` sec
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