If accelration of A is `2m//s^(2)` towards left and accleration of B is `1 m//s^(2)` towards left, then accleration of C is:

Options

A. `1 m//s^(2)` downwards
B. `1 m//s^(2)` upwards
C. `2 m//s^(2)` downwards
D. `2 m//s^(2)` upwards

Answer

B

Explanation

`l_(1)+l_(2)+l_(3)+l_(4)+l_(5)=` constant
`rArr overset(..)(l_(1))+overset(..)(l_(2))+overset(..)(l_(3))+overset(..)(l_(4))+overset(..)(l_(5))=0`
`rArr a_(C)+a_(A)+(a_(A)-a_(B))+(-a_(B))+a_(C)=0`
`rArr 2a_(C)+2a_(A)-2a_(B)=0`
`rArr a_(C)=a_(B)-a_(A)=1-2=-1 ms^(-2)`
`rArr` Acceleration of C is `1 ms^(-2)` upwards