If angular velocity of a particle depends on the angle rotated 0 as `x = 0^(2) + 20`, then its angular accelaration a at 0 = 1 rad is:

Options

A. `8 rad//s^(2)`
B. `10 rad//s^(2)`
C. `12 rad//s^(2)`
D. None of these

Answer

C

Explanation

Given `omrga=theta^(2)+2theta`
`(domega)/(dtheta)=2theta+2`
`alpha=omega(domega)/(dtheta)=(theta^(2)+2theta)(2theta+2)`
at `theta=1`
`alpha=12 rad//sec^(2)`