A particle is kept fixed on as turntable rotating uniformly. As seen from the ground the particle goes in a circle,its speed is 20 cm/s and acceleration is 20 cm/s^2 The particle is now shifted to a new positon to make the radius half of the original value. The new values of the speed and acceleration will be

Options

A. `10 cm//s, 10 cm//s^(2)`
B. `10 cm//s, 80 cm//s^(2)`
C. `40 cm//s, 10 cm//s^(2)`
D. `40 cm//s, 40 cm'//s^(2)`

Answer

A

Explanation

`omega` and `alpha` remain same but v and `a_(T)` is proportional to r thus at half the radius,
`v'=v/2 & a'_(T) (a_(T))/2`