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In the diagram shown, the displacement o...

In the diagram shown, the displacement of particles is given as a function of time. The particle a is moving under constant velocity of `9 m//s`. The particle B is moving under variable acceleration. From time `t=0 s` to `t=6 s`. The average velocity of the particle B will be equal to :-

A

`2.5 m//s`

B

`4 m//s`

C

`9 m//s`

D

None

Text Solution

Verified by Experts

The correct Answer is:
C
As given `9=y//6rArr y=54 m`
Average velocity of particle
`B=("Displacement")/("time")=54/6=9 m//s`
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