A particle moves along `x`-axis and its `x`-coordinate changes with time as `x=u(t-2)+a(t-2)^(2)`

Options

A. The initial velocity of the particle is u
B. The acceleration of the particle is a
C. The acceleration of the particle is 2a
D. At `t=2s` particle is at the origin

Answer

C, D

Explanation

`x=u(t-2)+a(t-2)^(2)`…(i)
`v=(dx)/(dt)=u+2a(t-2)`
Therefore `v(0)=u-4a`
`a=(d^(2)x)/(dt^(2))=2a" "` Hence [C]
`x(2)=0`[From (i)]. Hence [D]