In quick succession, a large number of balls are thrown up vertically in such a way that the next ball is thrown up when the previous ball is at the maximum height. If the maximum height is `5 m`, then find the number of the balls thrown up per second (g=10 m s^(-2)).

Options

A. `40`
B. `50`
C. `60`
D. `120`

Answer

C

Explanation

`h_("max")=u^(2)/(2g)rArr u=12xx10xx5=10 m//s`
`t_(H)=sqrt((2xx5)/10)=1 s` no. of balls in one min.
`=1xx60=60`