Acceleration versus velocity graph of a aprticle moving in a straight line starting form rest is as shon in figure. The corresponding velocity-time graph would be

Options

A.
B.
C.
D.

Answer

D

Explanation

`a=-kv+c [k gt 0, c gt 0]`
`int (dv)/(-kv+c)=intdtrArr-1/k ln(-kv+c)=t`
`rArr kv=c-e^(-kt)`