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A particle travels along the arc of a ci...

A particle travels along the arc of a circle of radius r . Its speed depends on the distance travelled l as `v=asqrtl` where a is a constant . The angel `alpha` between the vectors of total acceleration and the velocity of the particle is

A

`tan alpha=R/(2s)`

B

`tan alpha=(2a)/R`

C

`tan alpha=(2R)/s`

D

`tan alpha=s/(2R)`

Text Solution

Verified by Experts

The correct Answer is:
B

`tan alpha=v^(2)/Rxx1/(dv//dt)=(a^(2)s)/(Rav//2sqrt(s))=(2s)/R`
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