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STATEMENT-1: Two balls are dropped one a...

STATEMENT-1: Two balls are dropped one after the other form a tall tower. The distance between them increases linearly with time (elapsed after the second ball is dropped and before the first hits ground).
STATEMENT-2: Relative acceleration is zero, whereas relative velocity non-zero in the above situation.

A

Statement-I is true, Statement-II is true, Statement-II is correct explanation for Statement-I

B

Statement-I is true, Statement-II is true, Statement-II is NOT a correct explanation for Statement-I

C

Statement-I is true, Statement-II is false

D

Statement-I is false, Statement-II is true.

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The correct Answer is:
To solve the problem, we will analyze the two statements given and derive the necessary conclusions step by step. ### Step 1: Understanding the Problem We have two balls dropped from a tall tower, one after the other. We need to analyze the distance between the two balls after the second ball is dropped and before the first ball hits the ground. ### Step 2: Analyzing the Motion of the Balls - Let the first ball be dropped at time \( t = 0 \). - The second ball is dropped at time \( t = t_0 \) (let's say after a short interval). - The first ball will have fallen a distance \( h_1 = \frac{1}{2} g t^2 \) after time \( t \). - The second ball, dropped at \( t_0 \), will fall a distance \( h_2 = \frac{1}{2} g (t - t_0)^2 \) after the same time \( t \). ### Step 3: Finding the Distance Between the Balls The distance \( y \) between the two balls at time \( t \) after the second ball is dropped can be expressed as: \[ y = h_1 - h_2 \] Substituting the expressions for \( h_1 \) and \( h_2 \): \[ y = \frac{1}{2} g t^2 - \frac{1}{2} g (t - t_0)^2 \] Expanding \( (t - t_0)^2 \): \[ y = \frac{1}{2} g t^2 - \frac{1}{2} g (t^2 - 2tt_0 + t_0^2) \] Simplifying: \[ y = \frac{1}{2} g (2tt_0 - t_0^2) \] This shows that the distance \( y \) depends linearly on time \( t \) (since \( t \) is the variable). ### Step 4: Analyzing Relative Velocity and Acceleration - The acceleration of both balls is \( g \) (downward). - The relative acceleration between the two balls is: \[ a_{rel} = a_1 - a_2 = g - g = 0 \] - The relative velocity between the two balls can be calculated as: \[ v_{rel} = v_1 - v_2 \] Since both balls are accelerating downward, the relative velocity is non-zero. ### Conclusion - **Statement 1**: The distance between the two balls increases linearly with time. **True.** - **Statement 2**: The relative acceleration is zero, while the relative velocity is non-zero. **True.** - Therefore, both statements are true, and Statement 2 correctly explains Statement 1. ### Final Answer Both statements are true, and Statement 2 is the correct explanation for Statement 1. ---

To solve the problem, we will analyze the two statements given and derive the necessary conclusions step by step. ### Step 1: Understanding the Problem We have two balls dropped from a tall tower, one after the other. We need to analyze the distance between the two balls after the second ball is dropped and before the first ball hits the ground. ### Step 2: Analyzing the Motion of the Balls - Let the first ball be dropped at time \( t = 0 \). - The second ball is dropped at time \( t = t_0 \) (let's say after a short interval). ...
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