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A projectile is given an initial velocit...

A projectile is given an initial velocity of `(hati+2hatj) m//s,` where `hati` is along the ground and `hatj` is along the vertical. If `g = 10 m//s^(2),` the equation of its trajectory is:

A

`y=x-5x^(2)`

B

`y=2x-5x^(2)`

C

`4y=2x-5x^(2)`

D

`4y=2x-25x^(2)`

Text Solution

Verified by Experts

The correct Answer is:
2
`u=sqrt(5)` and `tan theta=2`
so by `y=x tan theta-(gx^(2))/(2u^(2))(1+tan^(2) theta)`
`rArr y=2x-(10x^(2))/(2xx5) (1+4)rArr y=2x-5x^(2)`
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