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The weight of 350 ml a diatomic gas at 0...

The weight of 350 ml a diatomic gas at `0^(@)C` and 2atm pressure is 1 gm.The weight of one atom is :-

A

`(16)/(N_(A))`

B

`(32)/(N_(A))`

C

`16N_(A)`

D

`32N_(A)`

Text Solution

Verified by Experts

The correct Answer is:
A
PV = nRT
` (2xx350)/(1000) = (1)/(Mw)xx0.082xx273`
Mw = 32
wt of molecule of diatomic molecule `A_(2) = (32)/(N_(A))`
wt of 1 atom of diatomic molecule
` A_(2) = (32)/(N_(A))xx(1)/(2)=(16)/(N_(A))`
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