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Boron has two isotopes, B-10 and B-11. T...

Boron has two isotopes, B-10 and B-11. The average atomic mass of boron is found to be 10.80u. Calculate the percentage of abundance of these isotopes.

A

80

B

20

C

25

D

75

Text Solution

Verified by Experts

The correct Answer is:
B
Hence to maintain the weight of 1 mole, value of A vogadro constant gets doubled
Let abondance of B-10 be xx and B-11 be 100-x Avg. mass=
`(M_(1)X_(1)+M_(2)X_(2))/(X_(1)+X_(2))rArr((10xxX)+[11xx(100-X)])/(100)=10.80`
rArr X = 20
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