A compound contain 3.4% by weight of sulphur, the minimum molecular wt of compound is:-

Options

A. 941.76
B. 944
C. 945.27
D. None

Explanation

To find the minimum molecular weight of a compound that contains 3.4% by weight of sulfur, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the given data**:
- The percentage by weight of sulfur in the compound is 3.4%.
- The atomic weight of sulfur (S) is 32 g/mol.

2. **Use the formula for percentage by weight**:
\[ \text{Percentage weight} = \frac{\text{Atomicity} \times \text{Atomic weight} \times 100}{\text{Molecular weight}} \]
Here, we need to find the molecular weight (M) of the compound.

3. **Assume atomicity**:
- For the minimum molecular weight, we can assume the atomicity of sulfur in the compound is 1 (i.e., there is one atom of sulfur in the molecular formula).

4. **Substitute the known values into the formula**:
\[ 3.4 = \frac{1 \times 32 \times 100}{M} \]

5. **Rearrange the equation to solve for M**:
\[ M = \frac{1 \times 32 \times 100}{3.4} \]

6. **Calculate M**:
\[ M = \frac{3200}{3.4} \approx 941.76 \]

7. **Conclusion**:
- The minimum molecular weight of the compound is approximately 941.76 g/mol.

### Final Answer:
The minimum molecular weight of the compound is **941.76 g/mol**.

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