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For the formation of 3.65 g of HCl gas, ...

For the formation of 3.65 g of HCl gas, what volume of hydrogen gas and chlorine gas are required at NTP conditions?

A

1L, 1L

B

1.12 L, 2.24 L

C

3.65 L,1.83 L

D

1.12L,1.12 L

Text Solution

Verified by Experts

The correct Answer is:
D
`H_(2)+CI_(2) to 2HCI" "n _(HCI) (3.65)/(36.5) = 0.1 `
`{:(2gm,71 gm,73gm,),(1"mole",1"mole",2 "mole",):}`
here 2 mole HCI produced by 1 mole `H _(2)`
1 mole HCI produce by 0.05 mole
`n_(H2) = V _(CI2) = 0.05 xx 22.4 =1.12L`
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