There are two common oxides of sulphur, one of which contains `50% O_(2)` by weight, the other almost exactly `60%`. The weight of sulphur which combine with `1 g` of `O_(2)` (fixed) are in the ratio of

Options

A. `1:1`
B. `2:1`
C. `2:3`
D. `3:2`

Explanation

To solve the problem, we need to determine the weight of sulfur that combines with 1 gram of O₂ for two different oxides of sulfur, based on the given percentages of oxygen by weight in each oxide.

### Step-by-Step Solution:

1. **Identify the Oxides and Their Percentages**:
- Let the first oxide of sulfur contain 50% O₂ by weight.
- Let the second oxide of sulfur contain 60% O₂ by weight.

2. **Calculate the Weight of Sulfur in Each Oxide**:
- For the first oxide (50% O₂):
- If the total weight is assumed to be 100 grams, then:
- Weight of O₂ = 50 grams
- Weight of Sulfur (S) = 100 grams - 50 grams = 50 grams
- For the second oxide (60% O₂):
- If the total weight is assumed to be 100 grams, then:
- Weight of O₂ = 60 grams
- Weight of Sulfur (S) = 100 grams - 60 grams = 40 grams

3. **Determine the Weight of Sulfur that Combines with 1 gram of O₂**:
- For the first oxide:
- If 50 grams of O₂ combines with 50 grams of S, then for 1 gram of O₂:
- Weight of S = (50 grams S / 50 grams O₂) × 1 gram O₂ = 1 gram S
- For the second oxide:
- If 60 grams of O₂ combines with 40 grams of S, then for 1 gram of O₂:
- Weight of S = (40 grams S / 60 grams O₂) × 1 gram O₂ = 40/60 grams S = 2/3 grams S

4. **Calculate the Ratio of the Weights of Sulfur**:
- The weight of sulfur that combines with 1 gram of O₂ for the first oxide is 1 gram.
- The weight of sulfur that combines with 1 gram of O₂ for the second oxide is 2/3 grams.
- Therefore, the ratio of the weights of sulfur is:
- Ratio = (Weight of S from first oxide) : (Weight of S from second oxide)
- Ratio = 1 : (2/3) = 1 : (2/3) = 3 : 2

### Final Answer:
The weight of sulfur which combines with 1 gram of O₂ in the two oxides is in the ratio of **3 : 2**.