16 cc of `CO_(2)` are passed over red hot coke. The volume of
CO evolved is :-

Options

A. 18cc
B. 32cc
C. 16cc
D. 4cc

Explanation

To solve the problem of determining the volume of carbon monoxide (CO) evolved when 16 cc of carbon dioxide (CO₂) is passed over red hot coke, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Reaction**: The reaction between carbon dioxide (CO₂) and coke (carbon, C) at high temperatures can be represented as:
\[ \text{CO}_2 + \text{C} \rightarrow 2 \text{CO} \]
This indicates that 1 mole of CO₂ produces 2 moles of CO.

2. **Volume Relationship**: According to Avogadro's law, equal volumes of gases at the same temperature and pressure contain an equal number of molecules. Therefore, the volume of CO produced will be twice the volume of CO₂ consumed.

3. **Calculate the Volume of CO**: Given that we have 16 cc of CO₂, we can calculate the volume of CO produced:
\[ \text{Volume of CO} = 2 \times \text{Volume of CO}_2 = 2 \times 16 \text{ cc} = 32 \text{ cc} \]

4. **Final Answer**: The volume of CO evolved when 16 cc of CO₂ is passed over red hot coke is:
\[ \text{Volume of CO} = 32 \text{ cc} \]