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According to Bohr’s theory, the angular ...

According to Bohr’s theory, the angular momentum of an electron in `5^("th")` orbit is:

A

`25(h)/(pi)`

B

`1.0(h)/(pi)`

C

`10(h)/(pi)`

D

`2.5(h)/(pi)`

Text Solution

Verified by Experts

The correct Answer is:
D
`mvr=n(h)/(2pi)`
` =(5h)/(2pi)`
`2.5(h)/(pi)`
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