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In an atom which has 2K, 8L , 18 ...

In an atom which has 2K, 8L , 18 M and 2N electrons in the ground state . The total number of electrons having magnetic quantum number m=0 is

A

6

B

2

C

8

D

16

Text Solution

Verified by Experts

The correct Answer is:
A
nos of `e^(-)` =2+8+8+2=20
`1s^(2)2s^(2)2p^(6) 3s^(2)3p^(6) 4s^(2)`
m=0,s`=+(1)/(2) rArr` number of `e^(-)` = 6
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