Home
Class 12
CHEMISTRY
No of spectral line obtained when electr...

No of spectral line obtained when electron is provided will a photoon of energy of 11 ev (for H atom)

A

1

B

2

C

0

D

6

Text Solution

AI Generated Solution

The correct Answer is:
To determine the number of spectral lines obtained when an electron in a hydrogen atom is provided with a photon of energy 11 eV, we can follow these steps: ### Step 1: Understand the Energy Levels of Hydrogen The energy levels of a hydrogen atom are given by the formula: \[ E_n = -\frac{13.6 \, \text{eV}}{n^2} \] where \( n \) is the principal quantum number (1, 2, 3, ...). ### Step 2: Calculate the Energy Levels Calculate the energy for the first three energy levels (n = 1, 2, and 3): - For \( n = 1 \): \[ E_1 = -\frac{13.6 \, \text{eV}}{1^2} = -13.6 \, \text{eV} \] - For \( n = 2 \): \[ E_2 = -\frac{13.6 \, \text{eV}}{2^2} = -3.4 \, \text{eV} \] - For \( n = 3 \): \[ E_3 = -\frac{13.6 \, \text{eV}}{3^2} = -1.51 \, \text{eV} \] ### Step 3: Determine Energy Differences Calculate the energy differences between the levels: - Difference between \( n = 1 \) and \( n = 2 \): \[ \Delta E_{1 \to 2} = E_2 - E_1 = -3.4 \, \text{eV} - (-13.6 \, \text{eV}) = 10.2 \, \text{eV} \] - Difference between \( n = 1 \) and \( n = 3 \): \[ \Delta E_{1 \to 3} = E_3 - E_1 = -1.51 \, \text{eV} - (-13.6 \, \text{eV}) = 12.09 \, \text{eV} \] ### Step 4: Compare Photon Energy with Energy Differences The photon energy provided is 11 eV. Now, we check if this energy is sufficient for any transitions: - For the transition from \( n = 1 \) to \( n = 2 \): - Required energy: 10.2 eV (11 eV > 10.2 eV, so transition is possible) - For the transition from \( n = 1 \) to \( n = 3 \): - Required energy: 12.09 eV (11 eV < 12.09 eV, so transition is not possible) ### Step 5: Determine Possible Transitions Since the photon energy (11 eV) is sufficient for the transition from \( n = 1 \) to \( n = 2 \), but not sufficient for the transition from \( n = 1 \) to \( n = 3 \), the only possible transition is: - \( n = 1 \) to \( n = 2 \) ### Step 6: Calculate Spectral Lines Each transition corresponds to a spectral line. Since we have one valid transition (from \( n = 1 \) to \( n = 2 \)), we will have: - Number of spectral lines = 1 ### Final Answer The number of spectral lines obtained is **1**. ---
Promotional Banner

Topper's Solved these Questions

  • CHEMISTRY AT A GLANCE

    ALLEN|Exercise INORGANIC CHEMISTRY|300 Videos
  • CHEMISTRY AT A GLANCE

    ALLEN|Exercise ORGANIC CHEMISTRY|472 Videos
  • Chemical Equilibrium

    ALLEN|Exercise All Questions|30 Videos
  • ELECTROCHEMISTRY

    ALLEN|Exercise EXERCISE -05 [B]|38 Videos

Similar Questions

Explore conceptually related problems

Number of spectral lines in hydrogen atom is

The total number of spectral lines obtained when an electron jumps, from n = 5 to n =1 in a sample of hydrogen atoms.

The spectral line obtained when an electron jumps from n = 6 to n = 2 level in hydrogen atom belong to the

The spectral line obtained when an electron jumps from n = 6 to n = 2 level in hydrogen atom belongs to the

Number of spectral line produced when electron jumps from gamma line region of Balmer series to ground state in hydrogen atom.

In a mixture of sample of H-atoms and He ions, electrons in all the H-atoms and He^+ ions are present in n = 4^"th" state. Then, find maximum number of different spectral lines obtained when all the electrons make transition from n=4 upto ground state

The number of spectral lines obtained in Bohr spectrum of hydrogen atom when an electron is excited from 5^("th") orbit to ground level is:

What will be the number of spectral lines in infrared region when electron transition occur from n=7 to n=2 in hydrogen atom :

The number of spectral lines produced when an electron jumps from 5^(th) orbit to 2^(nd) orbit in the hydrogen atom is.

When an electron in the hydrogen atom in ground state absorb a photon of energy 12.1eV , its angular momentum