Home
Class 12
CHEMISTRY
For N(2)+3H(3) hArr 2NH(3)+"Heat"...

For `N_(2)+3H_(3) hArr 2NH_(3)+"Heat"`

A

`K_(P)=K_(C)`

B

`K_(P)=K_(C)RT`

C

`K_(P)=K_(C)(RT)^(-2)`

D

`K_(P)=K_(C)(RT)^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • CHEMISTRY AT A GLANCE

    ALLEN|Exercise INORGANIC CHEMISTRY|300 Videos

  • CHEMISTRY AT A GLANCE

    ALLEN|Exercise ORGANIC CHEMISTRY|472 Videos

  • Chemical Equilibrium

    ALLEN|Exercise All Questions|30 Videos

  • ELECTROCHEMISTRY

    ALLEN|Exercise EXERCISE -05 [B]|38 Videos

Similar Questions

Explore conceptually related problems

For the reversible reaction N_2(g) +3H_2(g) hArr 2NH_3(g) +"Heat" The equilibrium shifts in forward directions.

The yield of NH_(3) in the reaction N_(2)+3H_(2) hArr 2NH_(3) , Delta H =-22.08 kcal is affected by

In a chemical reaction N_(2)+3H_(2) hArr 2NH_(3) , at equilibrium point

K_(p) for the reaction N_(2)+3H_(2) hArr 2NH_(3) at 400^(@)C is 1.64xx10^(-4) atm^(-2) . Find K_(c) .

For the reversible reaction N_(2) (g) +3H_(2) (g) hArr 2NH_(3) (g) + " Heat" The equilibrium shifts in forward direction

A reaction N_(2)+ 3H_(2) hArr 2NH_(3) + 92 k.j is at equilibrium. If the concentration of N_(2) is increased the temperature of the system

In a mixture of N_(2) and H_(2) in the ratio 1:3 at 30 atm and 300^(@)C , the % of NH_(3) at equilibrium is 17.8 . Calculate K_(p) for N_(2)+3H_(2) hArr 2NH_(3) .

At 450^(@)C the equilibrium constant K_(p) for the reaction N_(2)+3H_(2) hArr 2NH_(3) was found to be 1.6xx10^(-5) at a pressure of 200 atm. If N_(2) and H_(2) are taken in 1:3 ratio. What is % of NH_(3) formed at this temperature?

For the reaction N_(2)(g) + 3H_(2)(g) hArr 2NH_(3)(g), DeltaH=?

For a reaction N_(2)+3H_(2)hArr2NH_(3) , the value of K_(C) does not depends upon: