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In the following equilibriums: I:A+2B ...

In the following equilibriums:
`I:A+2B hArr C, K_(eq)=K_(1) " " II: C+D hArr 3A, K_(eq)=K_(2) " " III: 6B+D hArr 2C, K_(eq)=K_(3)` hence:

A

`3K_(1)K_(2)=K_(3)`

B

`K_(1)^(3)K_(2)^(2K_(3)`

C

`3K_(1)K_(2)^(2)=K_(3)`

D

`K_(1)^(3)K_(2)=K_(3)`

Text Solution

Verified by Experts

The correct Answer is:
D
`3xxeq.(i)+eq.(ii)=eq.(iii)`
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