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The solubility of calcium phosphate (mol...

The solubility of calcium phosphate (molecular mass = M ) in water is W g per `100mL " at " 25^(@)C` . Its solubility product at `25^(@)C` will be approximately-

A

`10^(9)((W)/(M))^(5)`

B

`10^(7)((W)/(M))^(5)`

C

`10^(5)((W)/(M))^(5)`

D

`10^(3)((W)/(M))^(5)`

Text Solution

Verified by Experts

The correct Answer is:
B
`{:(Ca_(3)(PO_(4))_(2),hArr,3Ca^(+2),+,2PO_(4)^(-2)),(" "S,,3S,,2S):}`
100ml have = w gm
100 ml have `(w)/(100)xx1000=(wxx10)(M)`(solubility)
Now Ksp = `[Ca^(+2)]^(3)[PO_(4)^(-2)]^(2)`
`rArr[(wxx10xx3)/(M)]^(3)[(wxx10xx2)/(M)]^(2)`
Approx `= 10^(7)((w)/(M))^(5)`
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