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The solubility product of water of AgBr ...

The solubility product of water of AgBr is `4 xx 10^(-13)`. The aqueous solution of AgBr has the concentration of `Ag^(+)` as `1 xx 10^(-6)` mole per, litre, what is the concentration of `Br^(-)` ion?

A

`1xx10^(-6)mol" "L^(-1)`

B

`4xx10^(-8)mol" " L^(-1)`

C

`4xx10^(-7)mol" " L^(-1)`

D

`4xx10^(-19)mol" " L^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
C
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