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The number of moles of KMnO(4) required ...

The number of moles of `KMnO_(4)` required to oxidise `1 mol` of `Fe(C_(2)O_(4))` in acidic medium is

A

1.2

B

3.33

C

0.4

D

0.8

Text Solution

Verified by Experts

The correct Answer is:
A
`MnO_(4)^(-)+FeC_(2)O_(4)toMn^(+2)+Fe^(+3)+CO_(2)`
Equivlents of `MnO_(4)^(-)` = Equivlents of ` FeC_(2)O_(4)`
`X xx 5 = 2 xx3`
X = 1.2mol
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