Home
Class 12
CHEMISTRY
Moldydenum ("At. mass=96g//mol"^(-1)) cr...

Moldydenum `("At. mass=96g//mol"^(-1))` crystallizes as bcc crystal. If density of crystal is `10.3g//cm^(3)`, then radius of Mo atoms `(use N_(A)= 6 xx 10^(23))`:

A

11pm

B

314pm

C

135.96pm

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
C
`d=(ZxxM)/(a^(3)xxN_(A))`
`10.3=(2xx96)/(a^(3)xx6xx10^(23))`
`a=3.14xx10^(-8)cm=314"pm"`
`r=sqrt(3a)/(4)=135.96 "pm"`
Promotional Banner

Topper's Solved these Questions

  • CHEMISTRY AT A GLANCE

    ALLEN|Exercise INORGANIC CHEMISTRY|300 Videos

  • CHEMISTRY AT A GLANCE

    ALLEN|Exercise ORGANIC CHEMISTRY|472 Videos

  • Chemical Equilibrium

    ALLEN|Exercise All Questions|30 Videos

  • ELECTROCHEMISTRY

    ALLEN|Exercise EXERCISE -05 [B]|38 Videos

Similar Questions

Explore conceptually related problems

The edge length of unit cell of a metal having molecular weight 75 g mol^(-1) is 5 Å which crystallizes in cubic lattice. If the density is 2 g cc^(-3) , then find the radius of metal atom (N_(A) = 6 xx 10^(23)) . Give the answer in pm.

By X-ray diffraction it is found that nickel ("at mass"=59g "mol"^(-1)) , crystallizes in ccp. The edge length of the unit cell is 3.5 Å . If density of Ni crystal is 9.0g//cm^(3) , then value of Avogadro's number from the data is:

The edge length of unit cell of a metal (Mw = 24) having cubic structure is 4.53 Å . If the density of metal is 1.74 g cm^(-3) , the radius of metal is (N_(A) = 6 xx 10^(23))

If the density of wood is 0.6 "g/cm"^3 , what is the mass of 10 "cm"^3 ?

An element (atomic mass=250 u) crystallizes in a simple cubic. If the density of the unit cell is 7.2 g cm^(-3) ,what is the radius of the element ?

The number of atoms in 0.1 mol of a tetraatomic gas is ( N_(A) = 6.02 xx 10^(23) mol^(-1) )

Niobium crystallizes in body centred cubic structure. If its density is 8.55 g cm^(-3) , calculate the atomic radius of niobium. (Atomic mass of Nb = 93u , N_A = 6.02 xx 10^(23) mol^(-1) )

Each edge of a cubic unit cell is 400pm long. If atomic mass of the elements is 120 and its desity is 6.25g//cm^(2) , the crystal lattice is: (use N_(A)=6 xx 10^(23))

The number of atoms in 100 g an fcc crystal with density d = 10 g//cm^(3) and the edge equal to 100 pm is equal to

A element crystallises in a bcc structure. The edge length of its unit cell is 288 pm. If the density of the crystal is 7.3 g cm^(-3) , what is the atomic mass of the element ?