Home
Class 12
CHEMISTRY
The fraction of volume occupied by atoms...

The fraction of volume occupied by atoms in a face centered cubic unit cell is:

A

`(pi)/(6)`

B

`(pi)/(3sqrt2)`

C

`(pi)/(4sqrt2)`

D

`(pi)/(4)`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • CHEMISTRY AT A GLANCE

    ALLEN|Exercise INORGANIC CHEMISTRY|300 Videos
  • CHEMISTRY AT A GLANCE

    ALLEN|Exercise ORGANIC CHEMISTRY|472 Videos
  • Chemical Equilibrium

    ALLEN|Exercise All Questions|30 Videos
  • ELECTROCHEMISTRY

    ALLEN|Exercise EXERCISE -05 [B]|38 Videos

Similar Questions

Explore conceptually related problems

The fraction of volume occupied by atoms in a body centered cubic unit cell is:

The fraction of total volume occupied by atoms in a simple cube is

The fraction of total volume occupied by the atoms in a simple cubic is

Calculate the number of atoms in a face centred cubic unit cell.

The fraction of total volume occupied by the atom present in a simple cubic is

The fraction of total volume occupied by the atom present in a simple cubic is

In face -centered cubic unit cell, edge length is

In face -centered cubic unit cell, edge length is

packing fraction of a unit cell is drfined as the fraction of the total volume of the unit cell occupied by the atom(s). P.E=("Volume of the atoms(s) present in a unit cell")/("Volume of unit cell")=(Zxx(4)/(3)pir^(3))/(a^(3)) and % of empty space = 100- P.F.xx100 where Z= effective number of stoms in s cube . r= radius of a an atoms a = edge lenght of the cube Packing fraction in face centered cubic unit cell is :

The volume of atom present in a face-centred cubic unit cell of a metal ( r is atomic radius ) is