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At 40^(@)C, the vapour pressure of pure ...

At `40^(@)C`, the vapour pressure of pure liquids, benzene, and toluene, are `160 mm Hg` and `60 mm Hg`,respectively. At the same temperature, the vapour pressure of an equimolar solution of the two liquids, assuming the ideal solution, should be

A

140 mm of Hg

B

110 mm of Hg

C

220 mm of Hg

D

100 mm of Hg

Text Solution

Verified by Experts

The correct Answer is:
B
`P_(s)=P_(B)^(@)+X_(T)(P_(P)^(@)-P_(P)^(@))=160+(1)/(2)(60-160)=160-50=110`.
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