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On the basis of the following e^(@) valu...

On the basis of the following `e^(@)` values, the strongest oxidising agent is :-`{:(K_(+)+e^(-)toK,,,,E^(@)=-2.923V),(Mg^(+2)2e^(-)toMg,,,,E^(@)=-2.337V):}`

A

`K^(+)`

B

`Mg^(+2)`

C

K

D

Mg

Text Solution

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The correct Answer is:
To determine the strongest oxidizing agent from the given standard reduction potentials (E° values), we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Given Reactions and Their E° Values:** - The first reaction is: \[ K^+ + e^- \rightarrow K \quad (E° = -2.923 \, V) \] - The second reaction is: \[ Mg^{2+} + 2e^- \rightarrow Mg \quad (E° = -2.337 \, V) \] 2. **Understand the Concept of Oxidizing Agents:** - An oxidizing agent is a substance that gains electrons (is reduced) and in the process causes another substance to be oxidized. The stronger the oxidizing agent, the more positive its E° value will be. 3. **Compare the E° Values:** - The E° value for \( K^+ \) is -2.923 V. - The E° value for \( Mg^{2+} \) is -2.337 V. - Since -2.337 V is greater than -2.923 V, \( Mg^{2+} \) has a higher reduction potential. 4. **Determine the Strongest Oxidizing Agent:** - Since \( Mg^{2+} \) has a higher (less negative) E° value, it is a better oxidizing agent compared to \( K^+ \). - Therefore, \( Mg^{2+} \) is the strongest oxidizing agent among the given options. 5. **Conclusion:** - The strongest oxidizing agent is \( Mg^{2+} \). ### Final Answer: The strongest oxidizing agent is \( Mg^{2+} \). ---
To determine the strongest oxidizing agent from the given standard reduction potentials (E° values), we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Given Reactions and Their E° Values:** - The first reaction is: \[ K^+ + e^- \rightarrow K \quad (E° = -2.923 \, V) ...
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