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Consider the following relations for emf...

Consider the following relations for emf of a electrochemical cell :
(a) emf of cell = (Oxidation potential of anode) - (Reduction potential of cathode)
(b) emf of cell = (Oxidation potential of anode) + (Reduction potential of cathod)
(c) emf of cell = (Reduction potential of anode) + (Reduction potential of cathode)
(d) emf of cell = (Oxidation potential of anode) - (Oxidation potential of cathode)
Which of the above relations are correct ?

A

emf of cell = oxidation potential of anode - reduction potential of cathode

B

emf of cell = oxidation potential of anode + reduction potential of cathode

C

emf of cell = reduction potential of anode + reduction potential of cathode

D

All of these

Text Solution

Verified by Experts

The correct Answer is:
B
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Consider the following relations for emf of a electrochemical cell (i) emf of cell = (Oxidation potential of anode)-(Reduction potential of cathode) (ii) emf of cell = (Oxidation potential of anode)+(Reduction potential of cathode) (iii) emf of cell = (Reduction potential of anode)+(Reduction potential of cathode) (iv) emf of cell = (Oxidation potential of anode)-(Oxidation potential of cathode) Which of the above realtions are correct?

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