The weight of copper (At wt = 63.5) displaced by a quantity of electricity which displaces 5600 ml of `O_(2)` at STP will be :-

Options

A. 63.5 g
B. 31.5 g
C. 15.875 g
D. 127 g

Explanation

To find the weight of copper displaced by a quantity of electricity that displaces 5600 ml of O₂ at STP, we can follow these steps:

### Step 1: Convert the volume of O₂ to moles
At STP (Standard Temperature and Pressure), 1 mole of any gas occupies 22.4 liters or 22400 ml. Therefore, we can find the number of moles of O₂ in 5600 ml.

\[ \text{Moles of O}_2 = \frac{\text{Volume of O}_2}{\text{Molar Volume at STP}} = \frac{5600 \, \text{ml}}{22400 \, \text{ml/mol}} = \frac{5600}{22400} = \frac{1}{4} \, \text{moles} \]

### Step 2: Calculate the weight of O₂
The molecular weight of O₂ is 32 g/mol. To find the weight of O₂ displaced, we can use the formula:

\[ \text{Weight of O}_2 = \text{Moles of O}_2 \times \text{Molecular Weight of O}_2 \]

Substituting the values we have:

\[ \text{Weight of O}_2 = \frac{1}{4} \, \text{moles} \times 32 \, \text{g/mol} = 8 \, \text{grams} \]

### Step 3: Relate the weight of O₂ to the weight of copper
To find the weight of copper displaced, we can use the concept of equivalent weights. The equivalent weight of a substance is defined as its molecular weight divided by its valency. For copper (Cu), the atomic weight is 63.5 g/mol, and its equivalent weight is:

\[ \text{Equivalent weight of Cu} = \frac{\text{Molecular weight of Cu}}{2} = \frac{63.5}{2} = 31.75 \, \text{grams/equiv} \]

### Step 4: Set up the ratio of weights
Using the equivalent weights, we can set up the following relationship:

\[ \frac{\text{Weight of Cu}}{\text{Equivalent weight of Cu}} = \frac{\text{Weight of O}_2}{\text{Equivalent weight of O}_2} \]

The equivalent weight of O₂ (considering it is diatomic and has a valency of 2) is:

\[ \text{Equivalent weight of O}_2 = \frac{32}{2} = 16 \, \text{grams/equiv} \]

Now substituting the known values:

\[ \frac{\text{Weight of Cu}}{31.75} = \frac{8}{16} \]

### Step 5: Solve for the weight of copper
Cross-multiplying gives:

\[ \text{Weight of Cu} = 31.75 \times \frac{8}{16} = 31.75 \times 0.5 = 15.875 \, \text{grams} \]

However, we need to use the ratio of equivalent weights directly to find the weight of copper:

\[ \text{Weight of Cu} = \text{Weight of O}_2 \times \frac{\text{Equivalent weight of Cu}}{\text{Equivalent weight of O}_2} \]

Substituting the values:

\[ \text{Weight of Cu} = 8 \times \frac{31.75}{16} = 8 \times 1.984375 = 15.875 \, \text{grams} \]

### Final Calculation
However, we can also directly relate it to the molecular weight of copper:

\[ \text{Weight of Cu} = \text{Weight of O}_2 \times \frac{63.5}{32} \]

Calculating this gives:

\[ \text{Weight of Cu} = 8 \times \frac{63.5}{32} = 8 \times 1.984375 = 15.875 \, \text{grams} \]

### Conclusion
The weight of copper displaced by the quantity of electricity that displaces 5600 ml of O₂ at STP is approximately **15.875 grams**.

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