The number of electrons delivered at the cathode during electrolysis
by a current of 2 ampere in 120 seconds is
(charge on electron `=1.6xx10^(-19)C)` :-

Options

A. `3.75xx10^(20)`
B. `7.48xx10^(20)`
C. `1.5xx10^(21)`
D. `3xx10^(20)`

Explanation

To solve the problem of finding the number of electrons delivered at the cathode during electrolysis by a current of 2 amperes in 120 seconds, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the given values:**
- Current (I) = 2 A (amperes)
- Time (t) = 120 s (seconds)
- Charge on an electron (e) = \(1.6 \times 10^{-19} \, C\) (coulombs)

2. **Calculate the total charge (Q) using the formula:**
\[ Q = I \times t \]
Substituting the values:
\[ Q = 2 \, A \times 120 \, s = 240 \, C \]

3. **Use the relationship between total charge (Q), number of electrons (n), and charge of an electron (e):**
\[ Q = n \times e \]
Rearranging the formula to find the number of electrons (n):
\[ n = \frac{Q}{e} \]

4. **Substituting the values to find n:**
\[ n = \frac{240 \, C}{1.6 \times 10^{-19} \, C} \]

5. **Perform the calculation:**
\[ n = \frac{240}{1.6 \times 10^{-19}} = 1.5 \times 10^{21} \]

6. **Conclusion:**
The number of electrons delivered at the cathode during electrolysis is \(1.5 \times 10^{21}\).

### Final Answer:
The number of electrons delivered at the cathode is \(1.5 \times 10^{21}\).

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