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Given the standard electrode potentials ...

Given the standard electrode potentials
`K^(+)//K=-2.93V,Ag^(+)//Ag=0.80V`
`Hg^(2+)//Hg=0.79V`
`Mg^(2+)//Mg=-2.37V,Cr^(3+)//Cr=-0.74V`
Arrange these metals in their increasing order of reducing power.

A

`AggtHggtCrgtMggtK`

B

`KgtMggtCrgtHggtAg`

C

`KgtCrgtMggtAggtHg`

D

`CrgtMggtKgtHggtAg`

Text Solution

Verified by Experts

The correct Answer is:
B
Reducing power `prop(1)/(E_(RP))`
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