The electron affinity values (in `kJ mol^(-1)` ) of three halogens, X, Y
and Z are respectively -349, -333 and -325. Then X, Y and Z are respectively

Options

A. F,Cl,Br
B. Cl,F,Br
C. Cl,Br,F
D. Br,Cl,F

Answer

To determine which halogens correspond to the given electron affinity values of -349 kJ/mol, -333 kJ/mol, and -325 kJ/mol, we can follow these steps:

### Step 1: Understand Electron Affinity
Electron affinity is the amount of energy released when an electron is added to a neutral atom in the gas phase. The more negative the value, the more energy is released, indicating a stronger attraction for the added electron.

### Step 2: Identify the Halogens
The halogens in Group 17 of the periodic table include:
- Fluorine (F)
- Chlorine (Cl)
- Bromine (Br)
- Iodine (I)

### Step 3: Order of Electron Affinity
Generally, the electron affinity of halogens decreases as we move down the group:
- Fluorine (F) has the highest (most negative) electron affinity.
- Chlorine (Cl) has a slightly lower (less negative) electron affinity than fluorine.
- Bromine (Br) has an even lower (less negative) electron affinity than chlorine.
- Iodine (I) has the least negative electron affinity among the common halogens.

### Step 4: Compare Given Values
Now, we compare the given electron affinity values with the known trends:
- -349 kJ/mol
- -333 kJ/mol
- -325 kJ/mol

From the general trend:
- The most negative value (-349 kJ/mol) corresponds to Chlorine (Cl).
- The next value (-333 kJ/mol) corresponds to Fluorine (F).
- The least negative value (-325 kJ/mol) corresponds to Bromine (Br).

### Step 5: Assign Halogens to Values
Based on the above analysis:
- X = Chlorine (Cl) with an electron affinity of -349 kJ/mol
- Y = Fluorine (F) with an electron affinity of -333 kJ/mol
- Z = Bromine (Br) with an electron affinity of -325 kJ/mol

### Conclusion
Thus, the halogens X, Y, and Z are:
- X = Cl
- Y = F
- Z = Br

### Final Answer
X = Cl, Y = F, Z = Br

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