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Which of the following matched correctly...

Which of the following matched correctly: `{:(,I.P.,,Reason,),((A),NgtO,,"Half filled configuration",),((B),ZrltHf,,"Lanthanoid contraction",),((C),NagtK,,Z_("eff"),),((D),AlltGa,,"Transition contraction",):}`

A

Only A

B

A, B, C, D

C

Only C

D

Only C, D

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the correct matches between ionization potential (I.P.) and their respective reasons, we will analyze each option step by step. ### Step 1: Analyze Option A - **Elements:** Nitrogen (N) and Oxygen (O) - **Claim:** N has a greater ionization potential than O. - **Reason:** Half-filled configuration. **Analysis:** - Nitrogen has the electronic configuration of 2s² 2p³ (half-filled), while Oxygen has 2s² 2p⁴ (not half-filled). - Half-filled configurations are more stable due to symmetry and exchange energy. - Therefore, N has a higher ionization potential than O. **Conclusion:** Option A is correctly matched. ### Step 2: Analyze Option B - **Elements:** Zirconium (Zr) and Hafnium (Hf) - **Claim:** Zr has a lower ionization potential than Hf. - **Reason:** Lanthanoid contraction. **Analysis:** - As we move from Zr to Hf, we encounter the f-block elements (lanthanides) which cause poor shielding due to the filling of the f-orbitals. - This results in an increase in effective nuclear charge, leading to a higher ionization potential for Hf compared to Zr. **Conclusion:** Option B is correctly matched. ### Step 3: Analyze Option C - **Elements:** Sodium (Na) and Potassium (K) - **Claim:** Na has a greater ionization potential than K. - **Reason:** Z_eff (effective nuclear charge). **Analysis:** - As we move down the group from Na to K, the atomic size increases, and the effective nuclear charge felt by the outermost electron decreases. - This results in a lower ionization potential for K compared to Na. **Conclusion:** Option C is correctly matched. ### Step 4: Analyze Option D - **Elements:** Aluminum (Al) and Gallium (Ga) - **Claim:** Ga has a greater ionization potential than Al. - **Reason:** Transition contraction. **Analysis:** - Gallium has d-electrons, which lead to a poor shielding effect. This results in a higher effective nuclear charge compared to Al, thus increasing the ionization potential of Ga. **Conclusion:** Option D is correctly matched. ### Final Conclusion All options A, B, C, and D are correctly matched with their respective reasons. ### Final Answer **All options are correctly matched.** ---
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